ln(5x-3) = 0
5x-3 = 1
x = 3/5
Your notation is a bit odd. I think you mean
log5(x) = 3
x = 5^3 = 125
log2(32) = x
5 = x
because 32 = 2^5
log2(3x+1) = 4
3x+1 = 2^4 = 16
x = 5
^ is usually reserved for exponents, not used in logs.
Hey, I would love if someone could please look over my answers. I just learned this yesterday and want to make sure I did my hw correct. Thanks!!!
Solve for x. Round answers to four decimal places where appropriate:
6. ln(5x-3)=0 ans= x=3/5
7. log5^x=3 ans= x^3=5
8. log2^32=x ans= x=16
9. log2(3x+1)=4 ans= x=7/3
2 answers
Thank you again for your help! I thought it was seeming a little too easy for me to be doing it correctly.