Hey, I would love if someone could please look over my answers. I just learned this yesterday and want to make sure I did my hw correct. Thanks!!!

Solve for x. Round answers to four decimal places where appropriate:

6. ln(5x-3)=0 ans= x=3/5
7. log5^x=3 ans= x^3=5
8. log2^32=x ans= x=16
9. log2(3x+1)=4 ans= x=7/3

2 answers

ln(5x-3) = 0
5x-3 = 1
x = 3/5

Your notation is a bit odd. I think you mean

log5(x) = 3
x = 5^3 = 125

log2(32) = x
5 = x
because 32 = 2^5

log2(3x+1) = 4
3x+1 = 2^4 = 16
x = 5

^ is usually reserved for exponents, not used in logs.
Thank you again for your help! I thought it was seeming a little too easy for me to be doing it correctly.