Question

hey i need some help with a couple of questions please.....

change all bases to 2 then simplify fully

2^n x 4^n+1
8^n-2
(note that i cannot put the division line thingo in)

prove that:
a^m/n = n(outside radical sign)a^m (inside radical sign)

i don't know if you can understand that??? if not i will post a link 2 a word doc...

thanx 4 ur help!! :):)

Answer 1

I have a feeling you meant to type

2^n x 4^(n+1) or else the +1 would be a nuisance dangling term

change the last factor
4^(n+1) into [2^2]^(n+1) = 2^(2n+2)
so now you have
(2^n)(2^(2n+2))
= 2^(3n+2)

Answer 2

thanx,

actually the site cut off my question, what i tried to type was

2^n x 4^(n+1)
/
8^(n-2)

Answer 3

then I am sure you can finish the question if your realize that

8^(n-2)
= [2^3]^(n-2)
= 2^(3n-6)

Answer 4

thanks for the help, i appreciate it, i was unsure of where iwas going wrong, it was just my brackets i mucked up, thanx.