how to work out (x)(x)
-------- = 1.56
( 2-x)(2-x)
hey guys need some help here!!!
if 0.250mol of CO and 0.250mol of H2O were combined in a 125mL flask and the reaction allowed to reach equilibrium . Kc= 1.56. write the equ expression and calculate each substance
Co(g) +H2O(g) .... Co2(g) +H2(g)
2 answers
............CO + H2O ==> CO2 + H2
I...........2....2........0.....0
C...........-x...-x.......x.....x
E...........2-x..2-x......x.....x
Kc = (CO2)(H2)/(CO)(H2O)
1.58 = (x)(x)/(2-x)(2-x)
The right side is a perfect square so take the square root of each side.
1.256 = (x)/(2-x)
Solve for x
I...........2....2........0.....0
C...........-x...-x.......x.....x
E...........2-x..2-x......x.....x
Kc = (CO2)(H2)/(CO)(H2O)
1.58 = (x)(x)/(2-x)(2-x)
The right side is a perfect square so take the square root of each side.
1.256 = (x)/(2-x)
Solve for x