Question

hey can somebody help me , its like a hundred questions, im helping my cousin doing it...lol

cos=sin60
sin=cos45
tan=1/tan30

cos^2(90' -0)/1-cos - sin(90' - O)

Answer 1

A statement such as
cos = sin60 makes no sense, it is mathematical gibberish.

It probably says something like...
If cosØ = sin60°, find Ø

looks like your cousin is studying the trig relationships of complementary angles and related properties

for the first two,
cos A° = sin (90-A)°
so cos 30° = sin 60°
and
sin 45° = cos 45°

for the 3rd, tan 60° = 1/tan 30°

I will not attempt to make sense out of your last one.