Here is the math problem:

Question

The height of an object in free fall, or otherwise thrown into the air near the earth's surface, with initial vertical velocity v0 in feet per seconds, and from the initial height h0 in feet, at any given time t in seconds is given by the equation:

h(t)= -16t^2 + v0t + h0

At 1821 feet tall, the CN Tower in Toronto, Canada is the world's tallest...etc. Suppose an object is dropped from the top of the tower (just released not pushed) .

1. The equation above find h0 and v0
2. The height of the object 2.3 seconds after being released.

Please help, even if you could show me how to proper start this problem I would be thankful! :]

Answer 1

An object moving vertically is at the given heights at the specified times. Find the position equation
s =
1
2
at2 + v0t + s0
for the object.
At
t = 1 second, s = 146 feet

At
t = 2 seconds, s = 98 feet

At
t = 3 seconds, s = 18 feet