Here is my question:
A 200 N sphere 0.20 m\m in radius rolls, without slipping, 6.0 m down a ramp that is inclined 28 degrees with the horizontal. What is the angular speed of the sphere at the bottom of the hill if it starts from rest?
Do this with energy considerations:
changePE= rolling KE + translation KE
mg*6sin28 = 1/2 I w^2 + 1/2 mv^2
and of course, wr=v
mg*6sin28 = 1/2 I w^2 + 1/2 m (wr)^2
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