Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot?

1 answer

To simplify the problem, let's first convert the mixed numbers to fractions.

6 3/10 = (6 * 10 + 3)/10 = 63/10
3 1/5 = (3 * 5 + 1)/5 = 16/5

Now, let's subtract 16/5 from 63/10.

63/10 - 16/5 = (63 * 2 - 16 * 2)/(10 * 2)
= (126 - 32)/20
= 4/20
= 1/5

Therefore, Henry has 1/5 liters of water remaining in the pot.