Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot?

Question

A : 2 9/10
B : 3 1/5
C : 3 1/10
D : 9 1/2

Answer 1

First, we need to convert both the amount of water in the pot and the amount poured out to the same denominator.

6 3/10 liters can be written as 6 + 3/10 = 6 + 3/10 = 63/10 = 6 3/10 liters.

3 1/5 liters can be written as 3 + 1/5 = 3 + 1/5 = 16/5 = 3 1/5 liters.

Now we subtract the amount poured out from the amount in the pot:

6 3/10 - 3 1/5 = 6 3/10 - 3 1/5

The denominators are already the same, so we can subtract the whole numbers and the fractions separately:

(6 - 3) + (3/10 - 1/5) = 3 + 1/10

The fractions have the same denominator, so we can subtract them:

3 + 1/10 = 3 1/10.

Therefore, there are 3 1/10 liters of water remaining in the pot.

The answer is C: 3 1/10.