Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot

Answer 1

To solve the problem, we need to subtract the amount of water poured out from the initial amount of water.
Initial amount of water = 6 3/10 liters = 63/10 liters.
Amount of water poured out = 3 1/5 liters = 16/5 liters.
Remaining amount of water = Initial amount of water - Amount of water poured out = 63/10 liters - 16/5 liters.
To subtract the fractions, we need to have the same denominator.
Multiplying the numerator and denominator of the 2nd fraction by 2 gives us: 2 * (16/5) = 32/10 liters.
Remaining amount of water = 63/10 liters - 32/10 liters = (63 - 32)/10 liters = 31/10 liters.
Therefore, there are 31/10 liters of water remaining in the pot.

Answer 2

no