To understand the results of the mating between a normal (non-carrier) female and a hemophiliac male, we can use basic genetics regarding sex-linked traits.
Hemophilia is linked to the X chromosome. The alleles can be represented as:
- X^H: normal allele (non-hemophilia)
- X^h: allele for hemophilia
- The female (normal non-carrier) has two normal X chromosomes: X^H X^H.
- The hemophiliac male has one X chromosome with the hemophilia allele and one Y chromosome: X^h Y.
When determining the possible offspring:
- The female can only contribute an X^H chromosome to her offspring.
- The male can contribute either his X^h chromosome or his Y chromosome.
The possible combinations for their children are:
- Daughters: X^H from the mother and X^h from the father (X^H X^h) - they will be carriers (heterozygous).
- Sons: X^H from the mother and Y from the father (X^H Y) - they will be normal (non-hemophiliac).
Thus, the result of mating a normal, non-carrier female with a hemophiliac male will be:
- All sons are normal (X^H Y).
- All daughters are carriers (X^H X^h).
The correct answer is: a: All sons are normal, and all daughters are carriers (heterozygous).
1 answer