help with this problem pease

Metal Specific Heat (J/g-C)
Al (s) 0.900
Au(s) 0.129
Cu(s) 0.385
Fe(s) 0.444
Hg(l) 0.139
H2O(l) 4.184
C2H5OH(l) 2.46

A piece of metal at a temp of 101.0oC and a mass of 86.0 g is dropped into a beaker of water containing 75.0 ml at a temp. of 27.0oC. If the final temperature reached is 35.0oC, what is the identity of the metal?

1 answer

the sum of the heats gained is zero.
heatgainedmetal+heatgainedwater=0
86*cm*(35-101)+75*cw(35-27)=0
solve for cm.