320+725 = 1045 g = 1.045 kg
friction force = 1.045*9.81 * .4
F - friction force = 1.045 * 2.25 m/s^2
HELP!!
Two blocks of mass m1 = 320 g and m2 = 725 g are pushed by a force. The coefficient of kinetic friction between each block and the ground is 0.4. The blocks move together (with one pushing the other) with an acceleration of 225 cm/s2. What is the value of the applied force in Newtons? Hint: Make sure to include the frictional force for each block.
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