we can only take logs of positive numbers
so 3x-8 > 0
3x > 8
x > 8/3
I will let you write it in the new-fangled notation.
In my time we used the above simple way of stating it.
Help solving this please. I am unsure how to do it?
Determine the domain of the following functions, write answer using interval notation.
P( x )=log2(3x-8)
2 answers
the domain of log(u) is u>0, regardless of the base of the logs. So, you need
3x-8 >0
x > 8/3
or,
(8/3,∞)
3x-8 >0
x > 8/3
or,
(8/3,∞)