after 1 hours, one ship has gone 25 km, the other 15 km
make a sketch, let the distance between them be x
straigh-forward case of the cosine law
x^2 = 25^2 + 15^2 - 2(25)(15)cos 60°
= ....
you do the arithmetic.
(I got appr 21.8 km)
Help!
Ships A and B leave port at the same time and sail on straight paths making an angle of 60 degrees with each other. HOw far apart are the ships at the end of 1 hour if the speed of ship A is 25 km/h and that of ship B is 15 km/h?
2 answers
Thanks a lot.
3 answers