well, disallowing x = -1 because that would cause division by zero, just solve
x^3 + 3x^2 - 2x + 7 = 11x + 11
x^3 + 3x^2 - 13x - 4 = 0
cubics aren't easy to solve in general, so look first for low-hanging fruit: +/- 1,2,4
Hmm. No joy there. Some iterative method, or wolframalpha will provide the three real roots:
-5.3, -0.3, 2.6
If the answer is 11, there's a typo somewhere in the problem. f(11) = 139.9
Help please
(x^3 + 3x^2 - 2x+7)/(x+1)=11
I don't how how to solve this at all-the answer should be 11 but I don't have a clue how to get it-please show me this one so I can hopefully do my homeowrk-we did this in class today but I don't understand it
1 answer
1 answer