Make a system.
let r represent records, and t represent tapes.
your system should be:
{2r+3t=$31
{3r+2t=$29
I suggest using elimination.
muliply ALL of the second equation by negative 3.
-3(3r+2t=$29
you'll get:
-9r-6t=-$87
Then multiply the first equation by a positive 2.
2(2r+3t=$31)
you'll get:
4r+6t=$62
Add the two new equations.
4r+6t=62
+ -9r-6t=-87
You should then eliminate the t's, and just get:
-5r=535
divide by -5.
Help please show steps to solve.
Two records and three tapes cost $31. Three records and two tapes cost $29. Find the cost of each records and each tape.
No examples to guide me.
thanks,
Carol
2 answers
actually wait, that gives you a negative answer......hmmm..........
Maybe you should disregard my work, but i know for a fact that you make a system the way i did. sorry.
Maybe you should disregard my work, but i know for a fact that you make a system the way i did. sorry.