csc^2 + sec^2
1/sin^2 + 1/cos^2
(sin^2 + cos^2)/(sin^2 cos^2)
1/(sin^2 cos^2)
sec^2 csc^2
Not sure what the 2nd line is saying
It's not an identity, just an expression.
Help please? I'm getting really confused.
>>>csc^2A+sec^2A = sec^2A csc^2A
>>>1+{(tan^2A)/(1+secA)]
And the "1" is getting me frustrated xO
2 answers
Oh sorry I forgot to put in secA so it should be 1+{(tan^2A)/(1+secA)] = secA