Help please. Am doing a past exam paper and I hit a road block with this question:

Question

Chloride in a brine solution is determined by a precipitation titration. A 10.00 mL
aliquot of the solution is titrated with 15.00mL of standard 0.1182 M AgNO3
solution. The excess silver is titrated with standard 0.1010 M KSCN solution,
requiring 2.38 mL to reach the red Fe(SCN)2+ endpoint. Calculate the
concentration of chloride in the brine solution, in g/1000mL.

Thank you! :)

Answer 1

Do I calculate the moles of KSCN and the moles of AgNO3
.
Moles reacted: moles AgNO3 - moles KSCN
Then say : C =mols reacted/volume(the 10 ml volume x 10 to the minus 3)

Then multiple mol/L by g/mol then convert to g/ml