help me Use the Quadratic Formula to solve N2=6n

Answer 1

n^2 = n.

n^2 - n = 0,
n = (-b+-sqrt(b^2-4ac)) / 2a.
n = (1+-sqrt(1-4*1*0)0 / 2,
n = (1+-sqrt(1-0)) / 2,
n = (1+-1) / 2,
n = (1+1) / 2 = 1.
n = (1-1) / 2 = 0/2 = 0.

Solution set: n = 1, and 0.

Answer 2

Correction:
n^2 = 6n.

n^2 - 6n = 0,
n = (6 +- sqrt(36-4*1*0)) / 2,
n = (6 +- sqrt(36-0)) / 2,
n = (6 +-sqrt(36)) / 2,
n = (6 +- 6) / 2,
n = (6+6) / 2 = 6.
n = (6-6) / 2 = 0/6 = 0.

Solution set: n = 6, and 0.

Answer 3

n^2= 6n
n^2-6n=0
n(n-6)=0
n=0,6