4x-2y=8 and x-y=0
well first of all you see immediately that y = x
so 2 x = 8 and x = 4 so y = 4
BUT you are supposed to do y = m x + b'
1. 4x-2y=8
-2y = -4x + 8
y = 2 x - 4 slope = 2 through (0, -4)
2. x-y=0
-y = - x
y = 1x + 0 slope = 1 through origin
help me please I do understand I got the wrong answer:
Solve the following system of linear equations by graphing
4x-2y=8 and x-y=0
1. 4x-2y=8
-2y/-2=4x/-2+8/-2
y=-2x/1-4 (0,-4)
2. x-y=0
-y/-1=x/-1+0/-1
y=1/-1+0 (0,0)
2 answers
how would you graph it?