just use the distance formula: d = √(∆x^2 + ∆y^2)
for #2, that would be
d = √((8-(-2))^2 + (-6-(-2))^2)
= √(10^2 + (-4)^2)
= √116
= 2√29
Help? I'm stuck.
For each graph, find (a)AB to the nearest tenth and (b)the coordinates of the midpoint of AB.
1. Coordinates are A(-9, -6) B(6,6)
2.A(-2,-2) B(8,-6)
3. A(0,3) B(-2,-2)
10 answers
would you divide 2 by 29?
Is #1 184.2?
#1 is √(225+144) = √369 = 19.2
for #2 the midpoint is (3,-4)
That is the average of the endpoints
That is the average of the endpoints
I got 369 and divided by 2. How's you get that answer?
SORRY! I was squaring it. Thanks for your help.
is one's midpoint answer (-1.5,-6)?
No, it's (-1.5,0) !!
Woah yall mad or sumthin?