h = 0.5g*t^2 = 100 m.
4.9t^2 = 100
t^2 = 20.40
Tf = 4.52 s. = Fall time.
Dx = Xo*Tf = 40m/s * 4.52s = 180.7 m.
help.
A rescue helicopter drops a package of emergency ration to a stranded party on the ground. If the helicopter is traveling horizontally at 40m/sec at a height of 100 m above the ground, where does the package strike the ground relative to the point at which it was released ?
A. 120 m
B. 160 m
C. 180 m
D. 220 m
answer is 180m , but how?
4 answers
First we need to find time by the help of height
100: 1/2(9.8)t^2
100: 4.9t^2
100/4.9: t^2
20.48:t^2
Taking root on both sides we get
t: 4.51Sec
Range: voxt
40 * 4.51: 180.4
Round off to 180
100: 1/2(9.8)t^2
100: 4.9t^2
100/4.9: t^2
20.48:t^2
Taking root on both sides we get
t: 4.51Sec
Range: voxt
40 * 4.51: 180.4
Round off to 180
Don’t forget sig figs! Which would bring u to 160m
(a) 180 (b) 40m/s (c) -44.1m/s
3 answers