Help: A 2 meter long, uniform bar with a mass of 46 kg is suspended from a pin so it can rotate freely. It is supported by a cable half a meter from the end. Find the tension force in the cable and the magnitude and direction of the reaction force at the wall for the bar to move

Answer 1

fw+T=46*9.8 vertical forces.
summing now about the wall..

46(9.8)*1=T*2

tension=23*9.8

fw= First equation=you do it.