I saw this one pass by me before.
Are you distinguishing between "x" and "X"?
If so, you have 4 variables with only 2 equations.
helo sir/madam
can u help me to solve this problem
solve the following simultaneous equation
logx Y+logy X=5/2
xy=64
2 answers
I will assume they are the same x
recall that loga b = log b/log a
so logxy = logy/logx
and logyx = logx/logy
so your equation can be written as:
logy/logx + logx/logy = 5/2
let logx/logy = a
then we have
1/a + a = 5/2
times 2a
2 + 2a^2 = 5a
2a^2 - 5a + 2 = 0
(a - 2)(2a - 1) = 0
a = 2 or a = 1/2
if a = 2
logx/logy = 2
logyx = 2
y = x^2
then in xy=64
x(x^2) = 64
x^3 = 64
x = 4 ------------> so x = 4 , y = 16
if a = 1/2
logyx = 1/2
x = y^(1/2) = √y
in xy=64
.....
x = 16, y = 4
recall that loga b = log b/log a
so logxy = logy/logx
and logyx = logx/logy
so your equation can be written as:
logy/logx + logx/logy = 5/2
let logx/logy = a
then we have
1/a + a = 5/2
times 2a
2 + 2a^2 = 5a
2a^2 - 5a + 2 = 0
(a - 2)(2a - 1) = 0
a = 2 or a = 1/2
if a = 2
logx/logy = 2
logyx = 2
y = x^2
then in xy=64
x(x^2) = 64
x^3 = 64
x = 4 ------------> so x = 4 , y = 16
if a = 1/2
logyx = 1/2
x = y^(1/2) = √y
in xy=64
.....
x = 16, y = 4