I assume the masses measured were before the experiment started; i.e., what you started with. If so, then change each of these to mols/dm^3.
The titrations were to find the equilibrium concentrations of the components. Use M x dm^3 = #mols,
convert # mols per whatever volume was in the equilibrium mixture, and substitute this value into the Kc expression.
Hello. In the class, we did the experiment to calculate the value of Kc for the following reaction:
CH3COOH+CH3CH2OH �ÌCH3COOCH2CH3+H2O
we measured the mass for 5 cm^3 of all 5 compound above:
CH3COOH 5.236 g
CH3CH2OH 4.021 g
CH3COOCH2CH3 5.020 g
H2O 5.020 g
HCl 5.098 g
when we titrate 2 mol dm^-3 HCl with the 1 mol dm-^3,10 cm^3 NaOH, the result was 4.85 cm^3.
we used the following mixtures in order to find Kc. We titrated with 1 mol dm^-3 NaOH using phenolphthalein as the indicator.
1) 5 cm^3 HCl, 5 cm^3 CH3COOCH2CH3. titration result 38.8 cm^3
2) 5 cm^3 HCl, 1cm^3 H20, 4 cm^ CH3COOCH2CH3.
titration result 35.7 cm^3
3) 5 cm^3 HCl, 2 cm^3 H2O, 3 cm^3 CH3COOCH2CH3.
titration result 30.2 cm^3
4) 5 cm^3 HCl,3 cm^3 H2O, 2 cm^3 CH3COOCH2CH3.
titration result 37.1 cm^3
5) 5 cm^3 HCl, 4 cm^3 CH3COOCH2CH3, 1 cm^3 CH3CH2OH.
titration result 31.5 cm^3
6) 5 cm^3 HCl, 4 cm^3 CH3COOCH2CH3, 1 cm^3 CH3COOH.
titration result 47.4 cm^3
7) 5 cm^3 HCl, 4 cm^3 CH3CH2OH, 1 cm^3 CH3COOH.
titration result 15.1 cm^3
8) 5 cm^3 HCl, 3 cm^3 CH3CH2OH, 2 cm^3 CH3COOH.
titration result 27.3 cm^3
How do we calculate the value of Kc ?
My teacher told us that the literature value is about 4, but I cannot get the correct/nearly correct answer.
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