Hello, I would like to know if you can help me with this problem the intergal of (cos (6x)+1), I’ve understood it as far as cos (1/2 (ax)) but where is the sqrt of 2 coming from?! Thank you.

Answer 1

integral of (cos (6x)+1) dx ??? from where to where or indefinite?
anyway if you do not have a typo, that is the sum of two integrals
cos 6x dx + 1 dx

(1/6) sin 6x + x + c

Answer 2

Definite

Answer 3

I mean indefinite

Answer 4

from where to where then and what is the a in (1/2)ax ?
Please check what you typed carefully.

Answer 5

Well, I did the indefinite integral and have no idea where your a and your square root come from.
There is something your are not telling us.

Answer 6

I have a photo of it, is there a way that I can post it on here?!