N = 14 g/mol
H = 1 g/mol
NH3 = 14+3 = 17 g/mol
3.68 g * 14/17 = 3.03 grams of N needed
by the way check grams of H
3.68 *3/17 = .65, just enough hydrogen:)
Hello, I was hoping that I could get some help with calculating the mass needed to completely react with this question.
In the following chemical reaction between H2 and N2 to produce NH3, what is the mass of N2 needed to completely react with 0.65 g H2 to produce 3.68 g of NH3?
3H2(g) + N2(g) → 2NH3(g)
I know that the chemical equation is already balanced, I am just not really sure where to go from here.
1 answer
1 answer