Hello, I was confused on this chemistry problem and I was wondering if someone could please help me.
1) Consider the following chemical reaction:
2CH3OH(I) + 3O2 (g) → 2CO2(g) + 4H2O(I)
Calculate the number of moles of CO2 produced when 11.25 mL of methanol CH3OH(I) reacted completely with O2(g). The density of methanol is .079 g/mL.
2 answers
*The density of methanol is 0.79 g/mL
If you had shown your work I could have found the error in half the time it takes to write all of this out.
2CH3OH(I) + 3O2 (g) → 2CO2(g) + 4H2O(I)
mass CH3OH = volume x density
mass CH3OH = 0.79 g/mL x 11.25 mL = ?
mols CH3OH = grams CH3OH/molar mass CH3OH = ?
mols CO2 = mols CH3OH x (2 mols CO2/2 mols CH3OH) = mols CO2 x 2/2 = ?
2CH3OH(I) + 3O2 (g) → 2CO2(g) + 4H2O(I)
mass CH3OH = volume x density
mass CH3OH = 0.79 g/mL x 11.25 mL = ?
mols CH3OH = grams CH3OH/molar mass CH3OH = ?
mols CO2 = mols CH3OH x (2 mols CO2/2 mols CH3OH) = mols CO2 x 2/2 = ?
1 answer