f' = -1/x^2
at (1,1) y' = -1
so, you have a point and a slope.
y-1 = -1(x-1)
you can probably find the intercepts from here, no?
Hello, I need help finding the intersection points B and C of the tangent A with for horizontal axis B and the vertical axis C.
hyperbola: f (x) = 1 / x
A = (1, 1)
Thanks for your help .
2 answers
B = (2, 0) and C = (0, 2) but we have explained how to find this result.