You cannot obtain CuCl2
mixing CuSO4 and NaCl because both are very soluble, and neither of the product species are insoluble.
Now if you teacher had asked if calcium chloride, instead of sodium chloride, you would get CuCl2 (aq) because CaSO4 is insoluble.
Hello I have a question about a reaction. I have to give the final products of mixed copper (II) sulfate, sodium chloride and finally copper. My teacher told me that it is formed a copper chloride, but which of the two that exists?
And how would it be the equations for the reactions?
I really don't understand what is the purpose of the copper here, if someone can explain me I would really be grateful.
2 answers
Or, your teacher wants the product to be CuCl (s), which is partially soluble. But I have some difficulty in that without predicting copper complex(s) first. So I dont know what your teacher is aiming for.