1.2L of .85M NaOH contains 1.02 moles NaOH
FeCl3 + 3NaOH = Fe(OH)3 + 3NaCl
But, you only have .25 moles of FeCl, so there is an excess of NaOH, since only 3*.25=.75 moles are needed. That means you will only get .25 moles of Fe(OH)3. Convert that to grams.
Not sure on the melting points, but you should be able to look them up.
Hello I have a couple questions first is
How man grams of Fe(OH)3 can be produced by the addition of .25 moles of Fecl3 to 1.2L of a .85M NaOH solution . I know we use the molarity equation MOlarity= moles of solute/ mass of solvent but i keep gettin gthe wrong answer
Also rank from highest to lowest melting point.
a. CH4 b. MgO c. H2O d. H2S
I thought it would be b d a c but i am wrong how can you tell?
3 answers
ITs the addition of .25
yes -- so the FeCl3 is dropped into the NaOH solution, and it all reacts, right? Am I missing something here?
3 answers