height = 1/2 g t^2 + Vo t + Ho
0 = -4.90 * .750^2 + Vo * .750 + 4.80
Hello, I had a question for physics, and I tried it out, however, I got the wrong answer.
The Question:If a rock takes 0.750s to hit the ground after being thrown down from a height of 4.80m, determine the rock's initial velocity.
My Work : The formula- d=vi*t+1/2*a*t^2
The isolated formula-(2*d)/(t*a)=vi
So it would be (2*4.80m)/(0.750s*9.81m/s^2)=vi
1.30m/s=vi
The correct answer is 2.72m/s[down]/
Could you please show me where I went wrong? Thank you!
1 answer