looks good to me.
Of course, the series is
∞
∑ 1/k! f(k) (x-2)k
The (2n)! series is for cos(x)
k=0
Hello! I am struggling with this problem:
Find the Taylor Series for sin(x-2) centered at c=3.
My work so far:
sin(1)+(x-3)cos(1)-(1/2)(x-3)^2sin(1)-(1/6)(x-3)^3cos(1)+(1/24)(x-3)^4sin(1)...
I know that the Taylor series for sign is typically: the summation from n=0 to infinity of ((-1)^n)/((2n)!) (x-c)^2n
I would appreciate any help! Thanks!
1 answer
1 answer