We need 2 moles of HCl for every mole of calcium hydroxide
we have 46.5 *10^-3 * .125 = 5.81 *10^-3 moles of calcium hydroxide
so we need
11.6 *10^-3 moles of HCl
.175 moles/liter * x liters = 11.6*10^-3 moles
x = 66.4 * 10^-3 liters = 66.4 mL
Hello! I am having a little difficulty answering these two questions on my homework, I was wondering if anyone could please help me out! Thank you!
1) Consider the following balanced chemical equation for the neutralization reaction of calcium hydroxide with hydrochloric acid to form calcium chloride and water.
Ca(OH)2(s) + 2HCl(aq) --> CaCl2(aq) + 2H2O(l)
How many mL of 0.175 M HCl are required to react with 46.5 mL of 0.125 M calcium hydroxide?
*Use a mole/mole ratio from the equation, and molarities.
2)Consider the following balanced chemical equation for the single replacement reaction of calcium metal with aqueous HCl to form calcium chloride and hydrogen gas.
Ca(s) + 2HCl(aq) --> CaCl2(aq) + H2(g)
How many mL of 3.31 M HCl are required to react with 2.94 g of calcium?
*Use the chemical equation to write a mole/mole ratio
2 answers
the second one is very similar except you need to know how many moles of Calcium are 2.94 grams
atomic mass of calcium = 40 grams/mole approx
so
2.94 g /40 g/mole = .0735 moles of Ca
so you will need twice that many moles of HCl
atomic mass of calcium = 40 grams/mole approx
so
2.94 g /40 g/mole = .0735 moles of Ca
so you will need twice that many moles of HCl
1 answer