first one is true
tan A = sinA/cosA
square both sides:
tan^2 A = sin^2 A/cos^2 A
watch the second one,
wouldn't the 2's on the right side cancel for you in your equation??
correct way:
since tanA = sinA/cosA
so
2(tanA) = 2(sinA/cosA) = 2sinA/cosA
Hello guys.
I am just wondering if tan^2 A (tan squared A) = sin^2 A /cos^2A
And 2tan A = 2sin A / 2cos A
This has been bothering me when I have to simplify trig.
Thanks in advance.
1 answer