well, you want
|tan(x)| = 1
tanx = 1 or -1
you know that tan π/4 = 1
so use that as your reference angle. The rest is easy.
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right?
Hello, could somebody please help me out with the following question? I would greatly appreciate some assistance.
Find all values of x in the interval [0, 2π] that satisfy the equation
3|tanx(x)|=3
5 answers
Steve, wouldn't I consider only the values for tanx=1 given the interval restriction?
Never mind, I understand it now. Thank you for your help, Steve.
no
|-1| = 1
|-1| = 1
I don't agree with dat ansa . . |tanx|=1 . . X =tan inverse of 1 which is 45 . .the ansa 4 x is 45
1 answer