The is a quadratic equation:
sin^2 x - sinx - 2 = 0
(sinx - 2)(sinx + 1) = 0
sinx = 2 , which is not possible
or
sinx = -1
x = 3π/2 or x = 270°
location on unit circle --- (0,-1)
period --- 2π
general solution
x = 3π/2 + 2kπ
Hello! Can someone help me with this?
Directions: Solve the equation
sin^2x-sinx=2
Location on Unit Ciricle:
Period:
General Solution:
1 answer
3 answers