Proofread your questions before you post them.
Even as the variance, height is a linear dimension and is not squared.
Heights of males are norm. dist. w/ u=180cm and o^2=16cm^2 while female heights have u=170cm and o^2=25cm^2.
a)random male and female selected. What is the probability that the male is >5 cm taller? What is the distribution avg of the 2 heights?
b)what is the distribution of the avg of the 2 heights?
Answering as much as possible would be amazing! :)
4 answers
I know it's just a linear dimension, I'm just assuming it's my prof's mistake (as he squared the sd to get variance). I simply copied directly from the paper.
The heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The U.S Army require's women's heights of 58 inches and 80 inches. Find the percentage.
Suppose that people's heights (in centimeters) are normally distributed, with a mean of 175 and a standard deviation of 6. We find the heights of 40 people.
2 answers