Hector went to the music store by heading due south at 3 m/s, then turning West and continuing at the same speed for another three blocks. Which of the following is true about Hector's velocity?(1 point)

Responses

Hector's velocity changed because his speed changed.
Hector's velocity changed because his speed changed.

Hector's velocity changed because his direction changed.
Hector's velocity changed because his direction changed.

Hector's velocity did not change because his direction did not change.
Hector's velocity did not change because his direction did not change.

Hector's velocity did not change because his speed did not change.

11 answers

Hector's velocity changed because his direction changed.

Even though his speed remained constant at 3 m/s, the change in direction from south to west results in a change in velocity, which is a vector quantity that depends on both speed and direction.

The graph shows a bicycle rider's motion during the first portion of a race.




What conclusion can be drawn about the rider's motion in the provided graph?

(1 point)
Responses

The rider maintained a constant speed during the time period between 0 and 20 seconds.
The rider maintained a constant speed during the time period between 0 and 20 seconds.

The rider rode downhill during the time period between 15 and 20 seconds.
The rider rode downhill during the time period between 15 and 20 seconds.

The rider slowed down during the time period between 15 and 20 seconds.
The rider slowed down during the time period between 15 and 20 seconds.

The rider did not move during the time period between 10 and 15 seconds
The rider did not move during the time period between 10 and 15 seconds
Skip to navigation

Without being able to see the actual graph, I can provide guidance based on common interpretations of motion graphs.

  1. Constant Speed: If the graph shows a straight, diagonal line from 0 to 20 seconds, it indicates that the rider maintained a constant speed during that time.

  2. Downhill Motion: If the graph shows a downward slope between 15 and 20 seconds, it would indicate that the rider is moving downhill.

  3. Slowing Down: If the line is curving downward or has a decreasing slope between 15 and 20 seconds, it suggests the rider slowed down.

  4. No Movement: If there is a horizontal line (on the time-axis), that would indicate the rider did not move during that time period.

Based on these descriptions, you can determine which option is correct by observing the graph. If indeed there is a straight line from 0 to 20 seconds, then the first option would be correct. If there is a slope that decreases between 15 and 20 seconds, then the third option about slowing down would be correct, and so forth.

A car that is traveling west at a constant rate has(1 point)
Responses

speed and velocity, but no acceleration.
speed and velocity, but no acceleration.

acceleration and speed, but no velocity.
acceleration and speed, but no velocity.

velocity, but neither acceleration nor speed.
velocity, but neither acceleration nor speed.

speed, but neither velocity nor acceleration.
speed, but neither velocity nor acceleration.

A car that is traveling west at a constant rate has speed and velocity, but no acceleration.

In this case, the car has a defined speed (how fast it is going) and a velocity (which includes the direction, west). Since it is traveling at a constant rate, there is no change in speed or direction, meaning there is no acceleration.

A student is investigating mass and acceleration. The student applies the same force to two boxes, as shown in the table.

The student claims that box 1 must have a smaller mass than box 2. Which argument best supports the student's claim?(1 point)
Responses

Lighter objects need less force than heavier objects to start moving but will accelerate at the same rate.
Lighter objects need less force than heavier objects to start moving but will accelerate at the same rate.

Lighter objects need greater force than heavier objects to start moving but will accelerate at the same rate.
Lighter objects need greater force than heavier objects to start moving but will accelerate at the same rate.

Heavier objects need less force than lighter objects to accelerate at the same rate.
Heavier objects need less force than lighter objects to accelerate at the same rate.

Heavier objects need greater force than lighter objects to accelerate at the same rate.
Heavier objects need greater force than lighter objects to accelerate at the same rate.
Skip to navigation

The argument that best supports the student's claim that box 1 must have a smaller mass than box 2 is:

Lighter objects need less force than heavier objects to start moving but will accelerate at the same rate.

This statement indicates that since the same force is applied to both boxes and assuming box 1 accelerates more than box 2, box 1 must have a smaller mass (as per Newton's second law, \( F = ma \)). If both boxes were subject to the same force and box 1 accelerates, then it indicates that box 1 is indeed lighter (smaller mass) compared to box 2.

While playing her soccer game, Samantha runs down the field at 10 meters per second. She has a constant speed and does not change direction. What is Samantha’s acceleration?(1 point)
Responses

The acceleration is 10 m/s^2 because her velocity increased.
The acceleration is 10 m/s^2 because her velocity increased.

The acceleration is 0 m/s^2 because her velocity increased.
The acceleration is 0 m/s^2 because her velocity increased.

The acceleration is 10 m/s^2 because her velocity did not change.
The acceleration is 10 m/s^2 because her velocity did not change.

The acceleration is 0 m/s^2 because her velocity did not change.

The correct response is:

The acceleration is 0 m/s² because her velocity did not change.

Since Samantha is running at a constant speed of 10 meters per second and not changing direction, her velocity remains constant. Therefore, her acceleration is zero, as acceleration is defined as the rate of change of velocity over time.

Two forces act on an object. One force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N directed south. What is the net force on the object?(1 point)
Responses

12 N south
12 N south

8 N north
8 N north

25 N north
25 N north

8 N south
8 N south

To find the net force on the object, you subtract the southward force from the northward force:

  • Northward force: 10 N
  • Southward force: 2 N

Net force = Northward force - Southward force = 10 N - 2 N = 8 N north.

Therefore, the correct answer is:

8 N north.