the sum of heats gained is zero. You will need the specific heat of the calorimeter.
Heats gained:
calorimeter=9.55*Ccal*(26.9-41.9)
water= 200.15*cwater(26.9-41.9)
icemelting=Hfice*9.7
this assumes the inital temp of ice was 0C
meltedicewater=9.7*Cwater*(26.9-0)
add all those (some are negative, some are positive), set equal to zero, then solve for Hfice
Heat of fusion of ice lab
Initial mass of empty cup calorimeter 9.55g
Initial mass of water 200.15g
Initial mass of ice + water 209.7g
Initial temp of water 41.9°C
Initial mass of ice 26.9g
Final mass of cup 9.55g
Final mass of water 227.05g
Final mass of cup + water 236.6g
Final temp of water 26.9°C
Calculate the heat of fusion of ice
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