θhe height h in feet of a car above the exit ramp of an amusement park′s free-fall ride can be modled by the equation h=−16t 6+s where t is the time in seconds after the car drops s is the starting height of the car in feet.

Question

θhe height h in feet of a car above the exit ramp of an amusement park′s free-fall ride can be modled by the equation h=−16t 6+s where t is the time in seconds after the car drops s is the starting height of the car in feet. How high above the car′s exit ramp should the ride′s designer start the drop in order for the riders to experience free-fall for at least 3 seconds?

Reiny · Answer

I don't know what h=−16t 6+s is supposed to say, but I know that h = -16t^2 is the relation between t seconds and the distance fallen in feet Since we just want to find the distance, let's use h = 16t^2 when t = 3 h = 16(9) = 144 feet If this is not what you want, then correct your typing.

Steve · Answer

If you mean h(t) = s - 16t^2 then we need s so that s-16*9 = 0 s = 144 ft

θhe height h in feet of a car above the exit ramp of an amusement park′s free-fall ride can be modled by the equation h=−16t<E> 6<E>+s where t is the time in seconds after the car drops s is the starting height of the car in feet.