he graph shows the radioactive decay of a bone that is found to contain 1/8 of the carbon-14 found in living animals today.
Approximately how old is the bone?
a
5,730 years
b
11,460 years
c
17,190 years
d
22,920 years
1 answer
The half-life of carbon-14 is approximately 5,730 years. Since the bone contains 1/8 of the carbon-14 found in living animals today, it can be inferred that it has undergone 3 half-lives (1/2 * 1/2 * 1/2 = 1/8). Therefore, the approximate age of the bone is 5,730 years * 3 = <<5730*3=17190>>17,190 years. The answer is c) 17,190 years.