To determine which combination of food items (a) and attractions (b) Leo can afford with his $15 budget, we can use the expression \(4a + 2b \leq 15\).
Let's analyze each option:
-
2 food items and 4 attractions:
\(a = 2\), \(b = 4\)
Total cost = \(4(2) + 2(4) = 8 + 8 = 16\) (exceeds budget) -
0 food items and 8 attractions:
\(a = 0\), \(b = 8\)
Total cost = \(4(0) + 2(8) = 0 + 16 = 16\) (exceeds budget) -
1 food item and 5 attractions:
\(a = 1\), \(b = 5\)
Total cost = \(4(1) + 2(5) = 4 + 10 = 14\) (within budget) -
3 food items and 2 attractions:
\(a = 3\), \(b = 2\)
Total cost = \(4(3) + 2(2) = 12 + 4 = 16\) (exceeds budget)
The only combination that Leo can afford within his $15 budget is 1 food item and 5 attractions.