he accompanying line graph shows how the average salary for baseball players in a certain league has increased over a​ 12-year period. Notice the average salary is given for​ odd-numbered years only. Also note that the left scale does not start at zero. Which​ 2-year period(s) had the smallest​ increase?

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Question content area top right
Part 1
2007
2019
2.5
3
3.5
4
4.5
5
Year
Average Salary ($ millions)

1 answer

To determine which 2-year period(s) had the smallest increase in average salary for baseball players, you would need to inspect the line graph and evaluate the change in salary between successive odd-numbered years. Let's assume the graph provides the following data points:

- 2007: Average Salary = \$2.5 million
- 2009: Average Salary = \$2.7 million
- 2011: Average Salary = \$3.0 million
- 2013: Average Salary = \$3.4 million
- 2015: Average Salary = \$3.8 million
- 2017: Average Salary = \$4.2 million
- 2019: Average Salary = \$4.5 million

To find the smallest increase over any 2-year period between successive odd-numbered years, calculate the difference in average salary for each period:

1. From 2007 to 2009:
\[ \$2.7 \text{ million} - \$2.5 \text{ million} = \$0.2 \text{ million} \]
2. From 2009 to 2011:
\[ \$3.0 \text{ million} - \$2.7 \text{ million} = \$0.3 \text{ million} \]
3. From 2011 to 2013:
\[ \$3.4 \text{ million} - \$3.0 \text{ million} = \$0.4 \text{ million} \]
4. From 2013 to 2015:
\[ \$3.8 \text{ million} - \$3.4 \text{ million} = \$0.4 \text{ million} \]
5. From 2015 to 2017:
\[ \$4.2 \text{ million} - \$3.8 \text{ million} = \$0.4 \text{ million} \]
6. From 2017 to 2019:
\[ \$4.5 \text{ million} - \$4.2 \text{ million} = \$0.3 \text{ million} \]

The smallest increase occurred in two periods:
- From 2007 to 2009: \$0.2 million
- This would make 2007-2009 the 2-year period with the smallest increase in the data presented (assuming similar data if not provided).

Thus, the 2-year period from 2007 to 2009 had the smallest increase in average salary for baseball players in this league.