I don't know what reaction 3 is.
........HCOOH ==> H^+ + HCOO^-
I.......0.005.....0.......0
C.......-x........x.......x
E......0.005-x....x.......x
Substitute the E line into the Ka expression and solve for x = H^+.
HCOOH(aq) <-----> H^+ (aq)+ HCOO^-(aq)
The equilibrium constant (Ka) for Reaction 3 at 25 °C is 1.80 × 10−4 mol dm−3. Calculate the equilibrium concentration of hydrogen ions if the concentration of formic acid at equilibrium is 0.00500 mol dm−3
5 answers
Sorry I should have left that out, it's just the formula
HCOOH(aq) <-----> H^+ (aq)+ HCOO^-(aq)
HCOOH(aq) <-----> H^+ (aq)+ HCOO^-(aq)
The solution I posted stands.
OK thanks....
In the question, and in the example in the textbook there was no example of using an ICE table. Tables make assigning values so much easier
In the question, and in the example in the textbook there was no example of using an ICE table. Tables make assigning values so much easier
ICE tables are the baling wire of chemistry.