We can use the Pythagorean theorem to find the distance from Hawick to Kelso, since we have a right triangle formed with Hawick, Kelso, and Abbotsford:
Distance from Hawick to Kelso = sqrt((Distance from Hawick to Abbotsford)^2 + (Distance from Kelso to Abbotsford)^2)
Distance from Hawick to Kelso = sqrt((15 km)^2 + (17 km)^2)
Distance from Hawick to Kelso = sqrt(225 + 289)
Distance from Hawick to Kelso = sqrt(514)
Distance from Hawick to Kelso ≈ 22.7 km (rounded to the nearest tenth of a kilometer)
Therefore, the distance from Hawick to Kelso is approximately 22.7 kilometers.
Hawick is 15 kilometers south of Abbotsford, and Kelso is 17 kilometers east of Abbotsford.
What is the distance from Hawick to Kelso?
Round your answer to the nearest tenth of a kilometer.
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