Corrections:
f(x) = x^2 − 4x + 2
f^-1(x) at x = 5.
Having trouble with this question on my assignment. I got the rest answered.
Assume a domain A = {x ∈ ℝ | x ≥ 2} for the function f(x) = x2 − 4x + 2.
Find the value of the inverse f -1(x) at x = 5. Provide 4 decimal places.
I'm getting 5.0000 but I'm sure that it's wrong.
2 answers
well, is f(5) = 5? No.
So, f^-1(5) is not 5.
y = x^2-4x+2 = (x-2)^2 - 2
The inverse function, restricted to the domain above, is
f^-1(x) = 2+√(x+2)
so, f^-1(5) = 2+√7
So, f^-1(5) is not 5.
y = x^2-4x+2 = (x-2)^2 - 2
The inverse function, restricted to the domain above, is
f^-1(x) = 2+√(x+2)
so, f^-1(5) = 2+√7
18 answers