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Have 250 mL of a 0.80 M solution of silver nitrate AgNO3 dissolved in water. how many grams of AgNO3 does the solution contain

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250 mL of 0.8M solution means there are 0.2M of AgNO₃

The mole weight of AgNO₃ is

107.9 + 14.01 + 3*16.0 = 169.91g

You have .2M, or 33.99g

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