Factoring a quadratic and solving the corresponding quadratic equation are closely related.
in the first case I would consider solving it as
x^2 + 8x + 53 = 0
since the only factors of 53 are 1 and 53 itself, there is no way we can get that 8 in the middle.
using the formula we get imaginary roots, so the thing does not factor.
2.
4x^2 + 23x - 30 = 0
just use the quadratic formula,
I got x = (-23 ± √1009)/8
Have 2 questions:
1. Factor Trinomial competely
x^2 + 8x + 53 (reads as x squared plus 8x plus 53) I am thinking it is prime.
2. Solve
4x^2 + 23x - 30=0
(reads 4x squared plus 23x minus 30 equals zero
3 answers
we haven't used the quadratic formula yet. for #2 i m trying to find the factors of 30 that add to 23. not finding any..any idea
the second question reads as 40x squared plus 23x minus 30=0
1 answer