B. 2054
To find out how many students in the entire population should be female athletes, we can set up a proportion:
250 (sample size) is to 170 (female athletes in the sample) as 3020 (entire population size) is to x (unknown number of female athletes in the entire population):
250/170 = 3020/x
Cross multiply to solve for x:
250x = 170 * 3020
x = (170 * 3020) / 250
x = 2054
Therefore, there should be 2054 female athletes in the entire population of 3020 students.
Halls High school has a student population of 3020 in a sample of 250 students 170 of there were female athletes how many students in the entire population should be female athletes
A. 170
B. 2054
C. 2700
D. 320
9 answers
Ana wants to know the average student’s opinion of the dress code policy at her school which group of students should she survey in order to archive the most accurate results
A. thirty students who were in trouble for dress code
B. thirty of her friends
C. thirty randomly selected students from her school
D. thirty students who have never been in trouble for dress code
A. thirty students who were in trouble for dress code
B. thirty of her friends
C. thirty randomly selected students from her school
D. thirty students who have never been in trouble for dress code
C. thirty randomly selected students from her school
By surveying thirty randomly selected students from her school, Ana will get a more representative sample of the entire student population. This method helps in reducing bias and ensures that the results are more accurate and reflective of the average student's opinion of the dress code policy. Surveying only students who were in trouble for dress code, her friends, or students who have never been in trouble may introduce bias and not provide a true representation of the entire student body.
By surveying thirty randomly selected students from her school, Ana will get a more representative sample of the entire student population. This method helps in reducing bias and ensures that the results are more accurate and reflective of the average student's opinion of the dress code policy. Surveying only students who were in trouble for dress code, her friends, or students who have never been in trouble may introduce bias and not provide a true representation of the entire student body.
28 Blake recorded the number of minutes he ran on the treadmill each day for 2 weeks his data is in the table below. what is the difference in the median between the two weeks that he ran in his treadmill
A. 2 minutes
B. 3 minutes
C. 3.14 minutes
D. 5 minutes
A. 2 minutes
B. 3 minutes
C. 3.14 minutes
D. 5 minutes
To find the median for each week, we first need to arrange the data in ascending order and then find the middle value.
Week 1 data: 20, 25, 30, 25, 20, 30, 30
Median for week 1 = (25 + 25) / 2 = 25 minutes
Week 2 data: 15, 30, 40, 25, 30, 20, 25
Median for week 2 = (25 + 30) / 2 = 27.5 minutes
The difference in the median between week 1 and week 2 would be:
27.5 - 25 = 2.5 minutes
The closest answer choice to this difference is A. 2 minutes.
Week 1 data: 20, 25, 30, 25, 20, 30, 30
Median for week 1 = (25 + 25) / 2 = 25 minutes
Week 2 data: 15, 30, 40, 25, 30, 20, 25
Median for week 2 = (25 + 30) / 2 = 27.5 minutes
The difference in the median between week 1 and week 2 would be:
27.5 - 25 = 2.5 minutes
The closest answer choice to this difference is A. 2 minutes.
Michael has a taken 6 quizzes so far in his Algebra 1 class Michael’s scores are the following 100,80,90,70,20 and 90 what is the mean score
To find the mean score, you need to add up all the scores and then divide by the total number of quizzes taken.
Sum of scores: 100 + 80 + 90 + 70 + 20 + 90 = 450
Total number of quizzes taken: 6
Mean score = Sum of scores / Total number of quizzes taken
Mean score = 450 / 6
Mean score = 75
Therefore, the mean score for Michael in his Algebra 1 class is 75.
Sum of scores: 100 + 80 + 90 + 70 + 20 + 90 = 450
Total number of quizzes taken: 6
Mean score = Sum of scores / Total number of quizzes taken
Mean score = 450 / 6
Mean score = 75
Therefore, the mean score for Michael in his Algebra 1 class is 75.
Michael has a taken 6 quizzes so far in his Algebra 1 class Michael’s scores are the following 100,80,90,70,20 and 90 what is the mode of the data
The mode is the value that appears most frequently in a set of data. In this case, Michael's scores are:
100, 80, 90, 70, 20, 90
The mode is 90 because it appears twice in the data set, which is more frequent than any other score.
Therefore, the mode of Michael's Algebra 1 quiz scores is 90.
100, 80, 90, 70, 20, 90
The mode is 90 because it appears twice in the data set, which is more frequent than any other score.
Therefore, the mode of Michael's Algebra 1 quiz scores is 90.